The probability that an appliance is currently being repaired is .5. If an apartment complex has 100 such appliances, what is the probability that at least 60 are currently being repaired? Use the normal approximation to the binomial.

Answer:.0287 Step-by-step explanation:For the binomial distribution, μ = np = 100(.5) = 50 σ = √(np(1-p)) = √(100(.5)(1-.5)) = √(100(.5)(.5)) = √25 = 5 Then, P(X >= 60) = using the continuity correction, P(X >= 59.5) = P(Z >= (59.5-50)/5) =P(Z >= 1.9) =1 - P(Z <= 1.9) (use the table in your book; I will use normsdist and report the answer to 4 decimal places, as is typical) 1 - normsdist(1.9) = .0287 (Note: the exact solution may be found in Excel using  1-binomdist (59,100,.5,TRUE) = .0284; note how the above result is close)